Optimal. Leaf size=199 \[ \frac{a^2 (6 b c-5 a d) \tanh ^{-1}\left (\frac{x \sqrt{b c-a d}}{\sqrt{c} \sqrt{a+b x^2}}\right )}{16 c^{7/2} (b c-a d)^{3/2}}+\frac{a x \sqrt{a+b x^2} (6 b c-5 a d)}{16 c^3 \left (c+d x^2\right ) (b c-a d)}+\frac{x \left (a+b x^2\right )^{3/2} (6 b c-5 a d)}{24 c^2 \left (c+d x^2\right )^2 (b c-a d)}-\frac{d x \left (a+b x^2\right )^{5/2}}{6 c \left (c+d x^2\right )^3 (b c-a d)} \]
[Out]
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Rubi [A] time = 0.306788, antiderivative size = 199, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19 \[ \frac{a^2 (6 b c-5 a d) \tanh ^{-1}\left (\frac{x \sqrt{b c-a d}}{\sqrt{c} \sqrt{a+b x^2}}\right )}{16 c^{7/2} (b c-a d)^{3/2}}+\frac{a x \sqrt{a+b x^2} (6 b c-5 a d)}{16 c^3 \left (c+d x^2\right ) (b c-a d)}+\frac{x \left (a+b x^2\right )^{3/2} (6 b c-5 a d)}{24 c^2 \left (c+d x^2\right )^2 (b c-a d)}-\frac{d x \left (a+b x^2\right )^{5/2}}{6 c \left (c+d x^2\right )^3 (b c-a d)} \]
Antiderivative was successfully verified.
[In] Int[(a + b*x^2)^(3/2)/(c + d*x^2)^4,x]
[Out]
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Rubi in Sympy [A] time = 43.4536, size = 175, normalized size = 0.88 \[ \frac{a^{2} \left (5 a d - 6 b c\right ) \operatorname{atan}{\left (\frac{x \sqrt{a d - b c}}{\sqrt{c} \sqrt{a + b x^{2}}} \right )}}{16 c^{\frac{7}{2}} \left (a d - b c\right )^{\frac{3}{2}}} + \frac{a x \sqrt{a + b x^{2}} \left (5 a d - 6 b c\right )}{16 c^{3} \left (c + d x^{2}\right ) \left (a d - b c\right )} + \frac{d x \left (a + b x^{2}\right )^{\frac{5}{2}}}{6 c \left (c + d x^{2}\right )^{3} \left (a d - b c\right )} + \frac{x \left (a + b x^{2}\right )^{\frac{3}{2}} \left (5 a d - 6 b c\right )}{24 c^{2} \left (c + d x^{2}\right )^{2} \left (a d - b c\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((b*x**2+a)**(3/2)/(d*x**2+c)**4,x)
[Out]
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Mathematica [A] time = 0.371867, size = 178, normalized size = 0.89 \[ \frac{\frac{\sqrt{c} x \sqrt{a+b x^2} \left (a^2 (-d) \left (33 c^2+40 c d x^2+15 d^2 x^4\right )+2 a b c \left (15 c^2+11 c d x^2+4 d^2 x^4\right )+4 b^2 c^2 x^2 \left (3 c+d x^2\right )\right )}{\left (c+d x^2\right )^3 (b c-a d)}-\frac{3 a^2 (6 b c-5 a d) \tan ^{-1}\left (\frac{x \sqrt{a d-b c}}{\sqrt{c} \sqrt{a+b x^2}}\right )}{(a d-b c)^{3/2}}}{48 c^{7/2}} \]
Antiderivative was successfully verified.
[In] Integrate[(a + b*x^2)^(3/2)/(c + d*x^2)^4,x]
[Out]
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Maple [B] time = 0.059, size = 13766, normalized size = 69.2 \[ \text{output too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((b*x^2+a)^(3/2)/(d*x^2+c)^4,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (b x^{2} + a\right )}^{\frac{3}{2}}}{{\left (d x^{2} + c\right )}^{4}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^2 + a)^(3/2)/(d*x^2 + c)^4,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.564068, size = 1, normalized size = 0.01 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^2 + a)^(3/2)/(d*x^2 + c)^4,x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x**2+a)**(3/2)/(d*x**2+c)**4,x)
[Out]
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GIAC/XCAS [A] time = 28.9007, size = 4, normalized size = 0.02 \[ \mathit{sage}_{0} x \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^2 + a)^(3/2)/(d*x^2 + c)^4,x, algorithm="giac")
[Out]